把一个值变为一连串的单词
编写一个函数，void written_amount(unsigned int amount,char *buffer);
他把amount表示的值转化为单词形式，并储存于buffer中，如amount的值为16312，那么buffer中存储的字符串应该是SIXTEEN THOUSAND THREE HUNDRED TWELVE 这个问题可以通过使用循环和条件语句来解决。首先，我们可以创建一个数组来存储数字对应的英文单词。然后，我们可以按照千位、百位、十位和个位的顺序将amount的每个数字转换成对应的英文单词，并将其存储到buffer中。
下面是一个可能的解决方案：
void written_amount(unsigned int amount, char *buffer) {
const char *digits[] = {
"ZERO", "ONE", "TWO", "THREE", "FOUR", "FIVE", "SIX", "SEVEN", "EIGHT", "NINE"
};
const char *teens[] = {
"TEN", "ELEVEN", "TWELVE", "THIRTEEN", "FOURTEEN", "FIFTEEN", "SIXTEEN", "SEVENTEEN", "EIGHTEEN", "NINETEEN"
};
const char *tens[] = {
"", "", "TWENTY", "THIRTY", "FORTY", "FIFTY", "SIXTY", "SEVENTY", "EIGHTY", "NINETY"
};
const char *powers[] = {
"", "THOUSAND", "MILLION", "BILLION"
};
if (amount == 0) {
strcpy(buffer, "ZERO");
return;
}
int index = 0;
while (amount > 0) {
if (amount % 1000 != 0) {
int part = amount % 1000;
int hundreds = part / 100;
int tens_and_ones = part % 100;
if (hundreds > 0) {
strcat(buffer, digits);
strcat(buffer, " HUNDRED ");
}
if (tens_and_ones >= 10 && tens_and_ones <= 19) {
strcat(buffer, teens);
} else {
int tens = tens_and_ones / 10;
int ones = tens_and_ones % 10;
if (tens > 0) {
strcat(buffer, tens);
strcat(buffer, " ");
}
if (ones > 0) {
strcat(buffer, digits);
strcat(buffer, " ");
}
}
strcat(buffer, powers);
strcat(buffer, " ");
}
amount /= 1000;
index++;
}
// 移除最后一个空格
buffer = '\0';
}
这个函数使用了四个字符串数组来存储数字对应的英文单词。在循环中，我们从amount的个位开始，依次将每个部分转换成英文单词，并将其拼接到buffer中。最后，我们需要移除最后一个空格。
请注意，这个解决方案假设buffer参数足够大，以便存储转换后的字符串。如果buffer的长度有限，请确保足够大以容纳转换后的字符串。 C/C++交流
下面是一个C++函数的实现，可以将给定的数值转换为单词形式并保存到缓冲区中：
#include <iostream>
#include <string>
void written_amount(unsigned int amount, char *buffer) {
// 数字对应的单词形式
std::string ones[] = {"", "ONE", "TWO", "THREE", "FOUR", "FIVE", "SIX", "SEVEN", "EIGHT", "NINE"};
std::string teens[] = {"TEN", "ELEVEN", "TWELVE", "THIRTEEN", "FOURTEEN", "FIFTEEN", "SIXTEEN", "SEVENTEEN", "EIGHTEEN", "NINETEEN"};
std::string tens[] = {"", "", "TWENTY", "THIRTY", "FORTY", "FIFTY", "SIXTY", "SEVENTY", "EIGHTY", "NINETY"};
std::string result;
if (amount == 0) {
result = "ZERO";
}
else {
// 处理万位数
if (amount >= 10000) {
unsigned int thousands = amount / 1000;
if (thousands >= 100) {
result += ones + " HUNDRED ";
thousands %= 100;
}
if (thousands >= 20) {
result += tens + " ";
thousands %= 10;
}
else if (thousands >= 10) {
result += teens + " ";
thousands = 0;
}
if (thousands > 0) {
result += ones + " ";
}
result += "THOUSAND ";
amount %= 1000;
}
// 处理百位和十位数
if (amount >= 100) {
result += ones + " HUNDRED ";
amount %= 100;
}
if (amount >= 20) {
result += tens + " ";
amount %= 10;
}
else if (amount >= 10) {
result += teens + " ";
amount = 0;
}
// 处理个位数
if (amount > 0) {
result += ones + " ";
}
}
// 将结果拷贝到缓冲区中
strncpy(buffer, result.c_str(), result.size());
buffer = '\0';
}
int main() {
unsigned int amount = 16312;
char buffer;
written_amount(amount, buffer);
std::cout << buffer << std::endl;
return 0;
}
这个函数使用了几个字符串数组来存储数字的单词形式，通过对给定的数值进行拆分和处理，将其转换为相应的单词，并将结果存储在缓冲区中。
希望这个回答对您有帮助！如果您有任何问题，请随时提问。
球一个最佳答案谢谢啦！这对我非常重要！{:10_254:}{:10_254:}{:10_254:} 可不可以用动态规划，或者递归{:9_228:} davidmou 发表于 2023-11-1 22:44
可不可以用动态规划，或者递归
有点难。。。
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