Python：每日一题 111

冬雪雪冬 · 发表于 2017-10-8 14:11:44

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本帖最后由冬雪雪冬于 2017-10-11 20:09 编辑

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题目：
生活中常常遇到激活码或邀请码，一般由数字和字母组成，题目要求生成由0~9和大写字母A~Z组成的12位随机码，为了避免混淆，这里去掉了数字0和字母O，数字1和字母I，数字2和字母Z，数字5和字母S，也就是用36-8=28个字符组成随机的代码，例如：
Q34E774RADFF

auyhin丶 · 发表于 2017-10-8 14:31:12

import random
temp = []
a = ord('A')
for i in range(10):
if(i == 1 or i == 2 or i == 5 or i == 0):
continue
temp.append(i)
for i in range(26):
asc = a + i
if(asc == ord('O') or asc == ord('I') or asc == ord('Z') or asc == ord('S')):
continue
temp.append(chr(asc))
#print(temp)
for j in range(12):
index = random.randint(0,len(temp)-1)
print(temp[index], end='')

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SixPy · 发表于 2017-10-8 15:16:09

>>> import string, random
>>> s = (string.digits+string.ascii_uppercase).translate(''.maketrans('','','1I2Z5S0O'))
>>> ''.join(random.choice(s)for i in range(12))

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bush牛 · 发表于 2017-10-8 18:42:13

from random import *
# 直接从28个元素随机出来
def f_one():
L = ['3','4','6','7','8','9',
'A','B','C','D','E','F',
'G','H','J','K','L','M',
'N','P','Q','R','T','U',
'V','W','X','Y']
return ''.join([x for x in choices(L, k=12)])
print(f_one())
# 随机unicode
def f_two():
d = {79,73,83,53}
s = ''
for i in range(12):
a = choice([randint(51, 57), randint(65, 89)])
if a in d:
a += 1
s += chr(a)
return s
print(f_two())

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王天豹 · 发表于 2017-10-8 21:13:06

本帖最后由王天豹于 2017-10-9 07:15 编辑

import string
import random
l=[]
a = string.ascii_uppercase
b = string.digits
for i in range(len(a)):
l.append(a[i])
for i in range(len(b)):
l.append(b[i])
for i in l:
if i == 'O' or i=='S' or i == 'I' or i == 'Z' or i == '0' or i == '1' or i == '2' or i == '5':
l.remove(i)
j=random.sample(l, 12)
q=''.join(j)
print(q)

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请教楼主，我这样写为什么不能去除“0”和“2”。

solomonxian · 发表于 2017-10-8 21:15:24

好像就是随机从范围内抽12个，也没有频率要求

import random
def fun():
domain = '346789ABCDEFGHJKLMNPQRTUVWXY'
return "".join(random.choice(domain) for _ in range(12))

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堕落之翼 · 发表于 2017-10-8 21:23:46

import random
x = '346789ABCDEFGHJKLMNPQRTUVWSY'
s = ''
for i in range(12):
s += random.choice(x)
print(s)

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口可口可 · 发表于 2017-10-9 00:02:27

本帖最后由口可口可于 2017-10-9 00:38 编辑

简单粗暴的解法：

import random
list='346789ABCDEFGHJKLMNPQRTUVWXY'
print("生成的12位随机码为：",end='')
for each in range(12):
print(random.choice(list),end='')

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销赃1994 · 发表于 2017-10-9 00:15:47

def yanzhengma():
import random
m = random.randint(51, 89)

while True:
      if m not in [53, 58, 59, 60, 61, 62, 63, 64, 73, 79, 83]:
         break
      m = random.randint(51, 89)

return m

names = locals()
for i in range(12):
names['x%s' % i] = yanzhengma()
print("%c%c%c%c%c%c%c%c%c%c%c%c" % (x0, x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11))

算是弄出来了，不过我想看看大神们的答案好改进一下。比如怎样生成自己想生成的随机数~~

wc365 · 发表于 2017-10-9 00:41:35

import random
a = list('ABCDEFGHIJKMNPQRTUVWXY346789')
b = []
for i in range(12):
index = random.randint(0,len(a)-1)
b.append(a[index])
c = ''.join(b)
print(c)

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jerryxjr1220 · 发表于 2017-10-9 09:19:45

本帖最后由 jerryxjr1220 于 2017-10-9 09:25 编辑

如果密码中的字符可重复用choices，如果不可重复可以用sample

from random import choices
print(''.join(choices('346789ABCDEFGHJKLMNPQRTUVWXY',k=12)))

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from random import sample
print(''.join(sample('346789ABCDEFGHJKLMNPQRTUVWXY',12)))

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sunnychou · 发表于 2017-10-9 09:25:43

本帖最后由 sunnychou 于 2017-10-9 10:11 编辑

import random
def rand():
a = []
for i in range(3, 10):
if i != 5:
a.append(i)
for i in range(65, 90):
if i != 73 and i != 79 and i != 83:
a.append(chr(i))
c = []
for i in range(0, 12):
d = random.randint(0, len(a)-1)
c.append(a[d])
# b = random.sample(a, 12)#生成无重复的12个数or生成又重复的12个数
return ''.join(str(i) for i in c)
print(rand())

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BngThea · 发表于 2017-10-9 09:33:09

import random
lista = [chr(i) for i in range(65,91)]
lista.remove('S')
lista.remove('Z')
lista.remove('I')
lista.remove('O')
listn = [str(i) for i in range(3,10)]
listn.remove('5')
assemble = lista + listn
verify = []
for x in range(12):
verify.append(random.choice(assemble))
print(''.join(verify))

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timeislife · 发表于 2017-10-9 10:39:37

修改了一下：

from random import randint
def password():
list1 = ["3","4","6","7","8","9","A","B","C","D","E","F","G","H","J","K","L","M","N","P","Q","R","T","U","V","W","X","Y","Z"]
list2 = []
i = 0
while i<12:
i+=1
list2.append(list1[randint(0,27)])
print(''.join(list2))
while True:
j = 0
n = int(input("请输入次数："))
while j<n:
j+=1
password()

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这样不会出错

Teagle · 发表于 2017-10-9 11:39:35

import string,random
print(''.join(random.sample([i for i in string.ascii_uppercase+string.digits if i not in "0125OISZ"],12)))

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胡先生 · 发表于 2017-10-9 12:28:42

import random

strs = ''
i=1
while  i < 13:

now_second = random.randint(1,2)

num = str(random.randint(4,9)) #数字

Letter_num  = random.randint(97, 122)

Letters=str(chr(Letter_num)) #字母
Letter = Letters.upper()
if now_second%2 == 0:
if num == 5:
continue
else:
strs = strs + num
i = i +1
else:
if Letter == 'O' or  Letter == 'I' or  Letter == 'S' or  Letter == 'Z':
continue
else:
strs = strs + Letter
i = i +1

print (strs)

sige · 发表于 2017-10-9 12:51:07

import random
list_num = [i for i in range(3,10)]
list_alp = [chr(i) for i in range(65,91)]
list_tot = list_num + list_alp
for i in [5,'O','I','S','Z']:
list_tot.remove(i)
result = ''
for i in range(12):
n = random.randint(0,27)
result = result + str(list_tot[n])

复制代码

运行结果：
M6BVA7GLT7FU
7FQF3UM7FJHG
LPMTTG9FURQ7

xindong · 发表于 2017-10-9 13:04:31

本帖最后由 xindong 于 2017-10-9 13:26 编辑

# -*- coding: utf-8 -*-

import random

char_list='346789ABCDEFGHIJKMNPQRTUVWXY'
iden_code=''
for i in range(0,12):
char_index=random.randint(0,27)
iden_code=iden_code +char_list[char_index]

print(iden_code)

张大象 · 发表于 2017-10-9 15:23:26

import random
L = [i for i in range(51,91) if i in range(51,58) or i in range(65,91)]
for i in(53,79,73,90,83):
L.remove(i)
M = []
for i in range(0,12):
s = random.randint(0,28)
M.append(chr(L[s]))
print(''.join(M))

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qwc3000 · 发表于 2017-10-9 15:47:42

本帖最后由 qwc3000 于 2017-10-9 15:52 编辑

import random
# 是字母进入此子程序
def isLetter():
# 随机产生一个65--89的数字
litter=random.randint(65, 89)
# 判断是不是 79 83  是重置
while litter==79 or litter==83 :
      litter = random.randint(65, 89)
# 将此数对应ASCII码中的字符返回
return chr(litter)
#是数字进入此子程序
def isNum():
num=random.randint(49, 57)
while num==50 or num==53 :
      num = random.randint(49, 57)
return chr(num)
# 定义一个邀请码的字符串
Invitation_code=""
# 定义个变量随机置数0,1  用来判断当前位置是字母还是数字
tmp=random.randint(0,1)
# 循环12次  生成邀请码
for i in range(1,13):
if tmp==1:
      Invitation_code+=isNum()
else:
      Invitation_code+=isLetter()
tmp=random.randint(0,1)
print(Invitation_code)

[技术交流] Python：每日一题 111

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