Python：每日一题 95（答题领鱼币）

冬雪雪冬 · 发表于 2017-9-8 07:55:40

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有一个多行的字符串，要给每行的开头加上数字，这个数字代表其后紧接着的与本行内容相同的行数。例如

FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC

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结果为

(3)FishC
(2)FishC
(1)FishC
(0)FishC
(1)Little turtle
(0)Little turtle
(0)Python
(0)FishC

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我的解法：

游客，如果您要查看本帖隐藏内容请回复

baicel21314 · 发表于 2017-9-8 08:49:40

how happy to this

sunnychou · 发表于 2017-9-8 08:52:13

BngThea · 发表于 2017-9-8 09:47:03

def addhead(list1):
count = 0
for i in range(0,len(list1)):
for j in range(i + 1,len(list1)):
if list1[j] == list1[i]:
count += 1
print('(' + str(count) + ')' + list1[i])
count = 0
list2 = ['FishC', 'FishC', 'FishC', 'FishC', 'Little turtle', 'Little turtle', 'Python', 'FishC']
addhead(list2)

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白牙 · 发表于 2017-9-8 09:49:46

本帖最后由白牙于 2017-9-8 10:58 编辑

list0= ['FishC', 'FishC', 'FishC', 'FishC', 'Little turtle', 'Little turtle', 'Python', 'FishC']
fuben_list=list0.split(',')
next = list1[-1]
list[-1]='(0)'+list1[-1]
for i in range(-2,-len(list1)-1,-1):
if list1==next:
count+=1
else:
count=0
next=list1
list0='(%d)'%conut+list
print('\n'.join(list1))

一条漂浮的枫叶 · 发表于 2017-9-8 10:21:28

学习一下

bush牛 · 发表于 2017-9-8 11:02:17

from itertools import groupby
a = '''
FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC
'''
s = [i for i in a.split('\n') if i != '']
b = [list(g) for k, g in groupby(s)]
for i in range(len(b)):
for j in range(len(b[i])):
print(len(b[i])-1-j,b[i][j])

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sky · 发表于 2017-9-8 11:05:16

print("\n".join(f"({s[i+1:].count(c)}){c}" for i,c in enumerate(s)))

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你看我屌不屌
py3.6以上

ChrisYang · 发表于 2017-9-8 11:27:04

s='''FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python\nFishC'''
ss=s.split('\n')
t=[]#全是0
for i in range(len(ss)):
t.append(0)
for i in range(1,len(ss)):
if ss[-i-1]==ss[-i]:
t[-i-1]=1+t[-i]
for i in range(len(ss)):
print("("+str(t[i])+")"+str(ss[i]))
————————————————————————————————
运行结果
===================== RESTART: D:\Python36-32\caogao.py =====================
(3)FishC
(2)FishC
(1)FishC
(0)FishC
(1)Little turtle
(0)Little turtle
(0)Python
(0)FishC
>>>

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BngThea · 发表于 2017-9-8 13:15:32

def addhead(list1):
count = 0
for i in range(0,len(list1)):
for j in range(i + 1,len(list1)):
if list1[j] == list1[i]:
count += 1
else:
break
print('(' + str(count) + ')' + list1[i])
count = 0
list2 = ['FishC', 'FishC', 'FishC', 'FishC', 'Little turtle', 'Little turtle', 'Python', 'FishC']
addhead(list2)

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之前没看到题目要求是紧跟着的

jerryxjr1220 · 发表于 2017-9-8 18:12:48

本帖最后由 jerryxjr1220 于 2017-9-8 18:17 编辑

from itertools import groupby
[print('(%d)%s' % (i, m)) for m,n in groupby(str1.split('\n')) for i in range(len(list(n))-1,-1,-1)]

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solomonxian · 发表于 2017-9-8 18:46:18

按换行符拆分，分组，按成员的数量贴上数字，再拼接起来

import itertools as it
def fun(s):
lst = ["".join(("(%d)"%k, i,"\n")) for i,j in it.groupby(s.split('\n')) for k in range(len(list(j))-1,-1,-1)]
return "".join(lst)[:-1]

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ChrisYang · 发表于 2017-9-8 18:56:33

哈哈，天天都有鱼币那

wc365 · 发表于 2017-9-9 00:19:16

a = '''
FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC
'''
list1 = a.split(sep='\n')[1:-1]
list2 = ['(0)' + list1[-1]]
for i in range(2,len(list1)+1):
if list1[-i] != list1[-i+1]:
list2.append('(0)' + list1[-i])
n = 0
else:
n += 1
list2.append('('+str(n)+')'+list1[-i])
for each in list2[::-1]:
print(each)

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醉挽丶南风 · 发表于 2017-9-9 13:48:35

s1='''FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC'''
s1=s1.split('\n')
num=len(s1)
for i in range(num):
count=0
for j in range(i+1,num):
if s1[i]==s1[j]:
count+=1
else:
break
s1[i]='('+str(count)+')'+s1[i]
print('\n'.join(s1))

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mintaka · 发表于 2017-9-9 16:36:37

def num(list,n):
m=0
if n==len(list)-1:
return m
for i in range(n+1,len(list)):
if list[i]==list[n]:
m+=1
else:
return m
list='''FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC'''
list=list.split('\n')
for i in range(0,len(list)):
print '('+str(num(list,i))+')'+list[i]

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樱花冷雨 · 发表于 2017-9-9 18:03:42

(3)FishC
(2)FishC
(1)FishC
(0)FishC
(1)Little turtle
(0)Little turtle
(0)Python
(0)FishC
为什么FishC有两个0？
怎样换成升（降）序不要零？

左手十字 · 发表于 2017-9-9 21:37:03

words='''Fishc
Fishc
Fishc
Fishc
Little turtle
Little turtle
Python
FishC'''
from collections import Counter
ss= dict(Counter(words.split('\n')))
for keys in ss:
for i in range(ss[keys]):
print('(%s)'%str(ss[keys]-i-1),keys)

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结果

(3) Fishc
(2) Fishc
(1) Fishc
(0) Fishc
(1) Little turtle
(0) Little turtle
(0) Python
(0) FishC

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苏格拉顶 · 发表于 2017-9-10 02:36:55

strVal = """
FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC
"""
newStrVal = strVal.split('\n')
strlist = [value.strip() for value in newStrVal if value.strip() is not '']
length = len(strlist)
for i in range(length):
j = i+1 if i+1<length else length
n = 0
for j in range(j,length):
if strlist[i] == strlist[j]:
n += 1
else:
break
print("(%d)%s" % (n,strlist[i]))

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Greenland · 发表于 2017-9-10 10:53:59

def counteRepeatedLines(string):
'给多行字符串的每行开头加上紧随其后重复的行数'
counter = 0
lines = []
splits = string.split('\n')
for i in range(len(splits)):
if i+1 == len(splits) or splits[i] != splits[i+1]:
while counter > 0:
lines.append('(%d)'% counter + splits[i])
counter -= 1
lines.append('(0)' + splits[i])
else:
counter += 1
return '\n'.join(lines)
print(counteRepeatedLines('FishC\nFishC\nFishC\nFishC\nLittle turtle\nLittle turtle\nPython\nFishC'))

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