Python：每日一题 111

qwc3000

import random
# 是字母进入此子程序
def isLetter():
    # 随机产生一个65--89的数字
    litter=random.randint(65, 89)
    # 判断是不是 79 83  是重置
    while litter==79 or litter==83 :
        litter = random.randint(65, 89)
    # 将此数对应ASCII码中的字符 返回
    return chr(litter)
#是数字进入此子程序
def isNum():
    num=random.randint(49, 57)
    while num==50 or num==53 :
        num = random.randint(49, 57)
    return chr(num)
# 定义一个邀请码的字符串
Invitation_code=""
# 定义个变量 随机置数0,1  用来判断当前位置是字母还是数字
tmp=random.randint(0,1)
# 循环12次  生成邀请码
for i in range(1,13):
    if tmp==1:
        Invitation_code+=isNum()
    else:
        Invitation_code+=isLetter()
    tmp=random.randint(0,1)
print(Invitation_code)

wyp02033

1. def f():
   
2.         chars = ['3','4','6','7','8','9','A','B','C','D','E','F','G','H','J','K','L','M','N','P','Q','R','T','U','V','W','X','Y']
   
3.         result = ''
   
4. 
   
5.         for i in range(12):
   
6. 
   
7.                 result += chars[r.randint(0,27)]
   
8.         return result

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墨黑

import random
random0 = ('3','4','6','7','8','9','Q','W','E','R','T','Y','U','P','A','D','F','G','H','J','K','L','X','C','V','B','N','M')
random1 = random.choice(random0)
random2 = random.choice(random0)
random3 = random.choice(random0)
random4 = random.choice(random0)
random5 = random.choice(random0)
random6 = random.choice(random0)
random7 = random.choice(random0)
random8 = random.choice(random0)
random9 = random.choice(random0)
random10 = random.choice(random0)
random11 = random.choice(random0)
random12 = random.choice(random0)
print(random1 + random2 + random3 + random4 + random5 + random6 + random7 + random8 + random9 + random10 + random11 + random12)

#求简单方法，感觉我的好累赘啊！新手一个

铁棍阿童木

1. # python每日一题（111）：实现12位随机码。
   
2. import random
   
3. invitation = "346789CDJMNOPBHUVIWXEFGAQRSTYZ"
   
4. code = ""
   
5. loop = 12
   
6. while loop:
   
7.    
   
8.     temp = random.choice(invitation)
   
9.     code += temp
   
10.     if code.count(temp) == 1:
    
11.         loop -= 1
    
12.     else:
    
13.         code += code[-1]
    
14. print(code)

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天使骑魔鬼

import random
str1 = '346789ABCDEFGHJKLMNPQRTUVWXY'
str2 = ''
for i in range(0,12):
    str2 += random.choice(str1)
print(str2)

铁棍阿童木

1. # python每日一题（111）：实现12位随机码。
   
2. import random
   
3. invitation = "346789ABCDEFGHJKLMNPQRTUVWXY"
   
4. code = ""
   
5. loop = 12
   
6. while loop:
   
7.     temp = random.choice(invitation)
   
8.     code = code + temp
   
9.     if code.count(temp) == 1:
   
10.         loop -= 1
    
11.     else:
    
12.         code = code[:-1] + ""
    
13. print(code)
    

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onedesigners

解题思路

1.由数字和字母组成
2.随机生成
3.数字：没有0，1，5 ，字母：没有o,z,s
4.字母为大写

1. import string
   
2. from random import *
   
3. characters = string.ascii_letters.upper()  + string.digits
   
4. password = "".join(choice(characters) for x in range(randint(8, 16)))
   
5. print password

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能力理解范围内 只能实现这个。。。 后续补充学习

whx

hh

liuwenqi

import random

String = 'abcdefghijklmnopqrstuvwxyzABCDEFGHJKLMNPQRTUVWXY346789'
passwd = ''.join(random.sample(String, 12))
print(passwd)

银色的色

自己

1. import random
   
2. def generate():
   
3.         str1 ="346789ABCDEFGHJKLMNPQRTUVWXYZ"
   
4.         gener = random.sample(str1,12)
   
5.         string =''
   
6.         for each in gener:
   
7.                 string +=each
   
8.         return string

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只能用笨的暴力方法了，

mass

1. from random import randint
   
2. def password():
   
3.     list1 = ["3","4","6","7","8","9","A","B","C","D","E","F","G","H","J","K","L","M","N","P","Q","R","T","U","V","W","X","Y","Z"]
   
4.     str1 = ''
   
5.     i = 0
   
6.     while i<12:
   
7.         i+=1
   
8.         str1 += list1[randint(0,28)]
   
9.     print(str1)
   
10.    
    
11. password()
    

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caiyouqian

ddddddd

八公子

from random import Random
str = ''
chars = 'ABCDEFGHJKLlMNPQRTUVWXY346789'
length = len(chars) - 1
random = Random()
for i in range(12):
    str+=chars[random.randint(0,length)]
print(str)

kanton

import random

def RandomMsg():
    tmp = random.randint(0,9)
    tmp2 = chr(random.randint(65,90))
    s = str(tmp) + str(tmp2)
    return s

s3 = ""
while len(s3)<12:
    s2 = random.choice(RandomMsg())
    if s2 in ['1','I','0','O','5','S','2','Z']:
        continue
    s3 += s2

print(s3)

了解2号

import random
num = random.choices("346789ABCDEFGHJKLMNPQRTUVWXY",K=12)
for i in num:
        print(i, end='')

了解2号

1. import random
   
2. num = random.choices('346789ABCDEFGHJKLMNPQRTUVWXY',k=12)
   
3. for i in num:
   
4.     print(i,end='')
   

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凉左

from random import randint

def activationCode():
    sourcestr = '346789ABCDEFGHJKLMNPQRTUVWXY'
    activecodelist = []
    for i in xrange(12):
        inx = randint(0, 27)
        activecodelist.append(sourcestr[inx])
    return ''.join(activecodelist)

了解2号

铁棍阿童木 发表于 2017-10-9 22:03

万一你的这个验证码中有某个字母重复，你这个不就奔溃了吗

见者生财

1. import string, random
   
2. s = (string.digits+string.ascii_uppercase)
   
3. n=[d for d in s if d not in ['1','I','2','Z','5','S','0','O']]
   
4. print(''.join(random.choice(n)for i in range(12)))
   

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ChrisYang

1. import random as r
   
2. leng=r.randint(8,14)#验证码的长度为8—14个单位长度
   
3. 
   
4. c=[3,4,6,7,8,9,'A','B','C','D','E','F','G','H','J','K',
   
5.    'L','M','N','P','Q','R','T','U','V','W','X','Y']
   
6. 
   
7. i=0
   
8. result=''
   
9. while i<leng:
   
10.     t=r.choice(c)
    
11.     result+=str(t)
    
12.    
    
13.     i+=1
    
14. else:
    
15.     print(result)
    
16. ===================== RESTART: D:\Python36-32\caogao.py =====================
    
17. MAVD9LKK8EWGK4
    
18. >>>
    
19. ===================== RESTART: D:\Python36-32\caogao.py =====================
    
20. 74Y8W3VD
    
21. >>>

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